Optimal. Leaf size=70 \[ \frac {5 a \sqrt {x}}{b^3}+\frac {5 x^{3/2}}{3 b^2}+\frac {x^{5/2}}{b (a-b x)}-\frac {5 a^{3/2} \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{b^{7/2}} \]
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Rubi [A]
time = 0.03, antiderivative size = 70, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 4, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.267, Rules used = {43, 52, 65, 214}
\begin {gather*} -\frac {5 a^{3/2} \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{b^{7/2}}+\frac {5 a \sqrt {x}}{b^3}+\frac {x^{5/2}}{b (a-b x)}+\frac {5 x^{3/2}}{3 b^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 43
Rule 52
Rule 65
Rule 214
Rubi steps
\begin {align*} \int \frac {x^{5/2}}{(-a+b x)^2} \, dx &=\frac {x^{5/2}}{b (a-b x)}+\frac {5 \int \frac {x^{3/2}}{-a+b x} \, dx}{2 b}\\ &=\frac {5 x^{3/2}}{3 b^2}+\frac {x^{5/2}}{b (a-b x)}+\frac {(5 a) \int \frac {\sqrt {x}}{-a+b x} \, dx}{2 b^2}\\ &=\frac {5 a \sqrt {x}}{b^3}+\frac {5 x^{3/2}}{3 b^2}+\frac {x^{5/2}}{b (a-b x)}+\frac {\left (5 a^2\right ) \int \frac {1}{\sqrt {x} (-a+b x)} \, dx}{2 b^3}\\ &=\frac {5 a \sqrt {x}}{b^3}+\frac {5 x^{3/2}}{3 b^2}+\frac {x^{5/2}}{b (a-b x)}+\frac {\left (5 a^2\right ) \text {Subst}\left (\int \frac {1}{-a+b x^2} \, dx,x,\sqrt {x}\right )}{b^3}\\ &=\frac {5 a \sqrt {x}}{b^3}+\frac {5 x^{3/2}}{3 b^2}+\frac {x^{5/2}}{b (a-b x)}-\frac {5 a^{3/2} \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{b^{7/2}}\\ \end {align*}
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Mathematica [A]
time = 0.08, size = 70, normalized size = 1.00 \begin {gather*} \frac {\sqrt {x} \left (-15 a^2+10 a b x+2 b^2 x^2\right )}{3 b^3 (-a+b x)}-\frac {5 a^{3/2} \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {a}}\right )}{b^{7/2}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.12, size = 60, normalized size = 0.86
method | result | size |
risch | \(\frac {2 \left (b x +6 a \right ) \sqrt {x}}{3 b^{3}}+\frac {a^{2} \left (-\frac {\sqrt {x}}{b x -a}-\frac {5 \arctanh \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{\sqrt {a b}}\right )}{b^{3}}\) | \(57\) |
derivativedivides | \(\frac {\frac {2 b \,x^{\frac {3}{2}}}{3}+4 a \sqrt {x}}{b^{3}}-\frac {2 a^{2} \left (-\frac {\sqrt {x}}{2 \left (-b x +a \right )}+\frac {5 \arctanh \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{2 \sqrt {a b}}\right )}{b^{3}}\) | \(60\) |
default | \(\frac {\frac {2 b \,x^{\frac {3}{2}}}{3}+4 a \sqrt {x}}{b^{3}}-\frac {2 a^{2} \left (-\frac {\sqrt {x}}{2 \left (-b x +a \right )}+\frac {5 \arctanh \left (\frac {b \sqrt {x}}{\sqrt {a b}}\right )}{2 \sqrt {a b}}\right )}{b^{3}}\) | \(60\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.49, size = 81, normalized size = 1.16 \begin {gather*} -\frac {a^{2} \sqrt {x}}{b^{4} x - a b^{3}} + \frac {5 \, a^{2} \log \left (\frac {b \sqrt {x} - \sqrt {a b}}{b \sqrt {x} + \sqrt {a b}}\right )}{2 \, \sqrt {a b} b^{3}} + \frac {2 \, {\left (b x^{\frac {3}{2}} + 6 \, a \sqrt {x}\right )}}{3 \, b^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.44, size = 167, normalized size = 2.39 \begin {gather*} \left [\frac {15 \, {\left (a b x - a^{2}\right )} \sqrt {\frac {a}{b}} \log \left (\frac {b x - 2 \, b \sqrt {x} \sqrt {\frac {a}{b}} + a}{b x - a}\right ) + 2 \, {\left (2 \, b^{2} x^{2} + 10 \, a b x - 15 \, a^{2}\right )} \sqrt {x}}{6 \, {\left (b^{4} x - a b^{3}\right )}}, \frac {15 \, {\left (a b x - a^{2}\right )} \sqrt {-\frac {a}{b}} \arctan \left (\frac {b \sqrt {x} \sqrt {-\frac {a}{b}}}{a}\right ) + {\left (2 \, b^{2} x^{2} + 10 \, a b x - 15 \, a^{2}\right )} \sqrt {x}}{3 \, {\left (b^{4} x - a b^{3}\right )}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 354 vs.
\(2 (63) = 126\).
time = 15.26, size = 354, normalized size = 5.06 \begin {gather*} \begin {cases} \tilde {\infty } x^{\frac {3}{2}} & \text {for}\: a = 0 \wedge b = 0 \\\frac {2 x^{\frac {3}{2}}}{3 b^{2}} & \text {for}\: a = 0 \\\frac {2 x^{\frac {7}{2}}}{7 a^{2}} & \text {for}\: b = 0 \\- \frac {15 a^{3} \log {\left (\sqrt {x} - \sqrt {\frac {a}{b}} \right )}}{- 6 a b^{4} \sqrt {\frac {a}{b}} + 6 b^{5} x \sqrt {\frac {a}{b}}} + \frac {15 a^{3} \log {\left (\sqrt {x} + \sqrt {\frac {a}{b}} \right )}}{- 6 a b^{4} \sqrt {\frac {a}{b}} + 6 b^{5} x \sqrt {\frac {a}{b}}} - \frac {30 a^{2} b \sqrt {x} \sqrt {\frac {a}{b}}}{- 6 a b^{4} \sqrt {\frac {a}{b}} + 6 b^{5} x \sqrt {\frac {a}{b}}} + \frac {15 a^{2} b x \log {\left (\sqrt {x} - \sqrt {\frac {a}{b}} \right )}}{- 6 a b^{4} \sqrt {\frac {a}{b}} + 6 b^{5} x \sqrt {\frac {a}{b}}} - \frac {15 a^{2} b x \log {\left (\sqrt {x} + \sqrt {\frac {a}{b}} \right )}}{- 6 a b^{4} \sqrt {\frac {a}{b}} + 6 b^{5} x \sqrt {\frac {a}{b}}} + \frac {20 a b^{2} x^{\frac {3}{2}} \sqrt {\frac {a}{b}}}{- 6 a b^{4} \sqrt {\frac {a}{b}} + 6 b^{5} x \sqrt {\frac {a}{b}}} + \frac {4 b^{3} x^{\frac {5}{2}} \sqrt {\frac {a}{b}}}{- 6 a b^{4} \sqrt {\frac {a}{b}} + 6 b^{5} x \sqrt {\frac {a}{b}}} & \text {otherwise} \end {cases} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.92, size = 69, normalized size = 0.99 \begin {gather*} \frac {5 \, a^{2} \arctan \left (\frac {b \sqrt {x}}{\sqrt {-a b}}\right )}{\sqrt {-a b} b^{3}} - \frac {a^{2} \sqrt {x}}{{\left (b x - a\right )} b^{3}} + \frac {2 \, {\left (b^{4} x^{\frac {3}{2}} + 6 \, a b^{3} \sqrt {x}\right )}}{3 \, b^{6}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 0.07, size = 61, normalized size = 0.87 \begin {gather*} \frac {2\,x^{3/2}}{3\,b^2}+\frac {4\,a\,\sqrt {x}}{b^3}+\frac {a^2\,\sqrt {x}}{a\,b^3-b^4\,x}+\frac {a^{3/2}\,\mathrm {atan}\left (\frac {\sqrt {b}\,\sqrt {x}\,1{}\mathrm {i}}{\sqrt {a}}\right )\,5{}\mathrm {i}}{b^{7/2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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